find the equation of the line that passes through (-2,3) and (1,2)
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x1=-2
x2=1
y1=3
y2=2
the equation is
y-y1 =(y2-y1)/(x2-x1) {x-x1}
y-3=-1/3 [x-(-2)]
y-3=-(x+2)/3
3y-7+x=0
x2=1
y1=3
y2=2
the equation is
y-y1 =(y2-y1)/(x2-x1) {x-x1}
y-3=-1/3 [x-(-2)]
y-3=-(x+2)/3
3y-7+x=0
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