Question

Find the equation of the line whose x intercept is 5 and which passes through the point (-3,2)

Answer 1

Solution :

Equation of a Line whose x - intercept

is 5 and which passes through the

point ( -3 , 2 ).

Let the point A( 5 , 0 ) on x - axis and

passing through the point B( -3, 2 ) is

A(5,0) = ( x1 , y1 ) ,

B(-3 , 2 ) = ( x2,y2),

y - y1 = [ (y2-y1)/(x2-x1)]( x -x1 )

=> y -0 = [(2-0)/(-3-5)](x-5)

=> y = ( 2/-8) ( x - 5 )

=> y = (-1/4) ( x - 5 )

=> 4y = -(x-5)

=> 4y + x -5 = 0

=> x + 4y - 5 = 0

••••

Answer 2

Answer:

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