Find the equation of the line with slope -0.25 and (-2,-4) on the line
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Slope m=-1/4
Point on the line is=(-2,-4)
Equation of a straight line passing through (_2,-4)and having slope - 1/4 is y +4=-1/4(x+2)
4y+16=-x-2
x+4y+18=0
Point on the line is=(-2,-4)
Equation of a straight line passing through (_2,-4)and having slope - 1/4 is y +4=-1/4(x+2)
4y+16=-x-2
x+4y+18=0
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