Question

Find the equation of the line with the given properties. Express the equation in general form or slope-intercept form.

Perpendicular to the line 5x+y=60; contains the point (10,9)

Answer 1

Answer:

5x-y=1

Step-by-step explanation:

slope of line 5x+y=60 (m1) : -x coefficient /y coefficient

m1 =-5

let the slope of other line be m2.

As lines are perpendicular

m1*m2=-1

So, -5*m2=-1

m2 =5

POINTS ARE (x1,y1)=(10,9)

SLOPE IS (5)

EQUATION IS GIVEN BY:

m2*x- x1=y-y1

5*x-10=y-9

5x - 10 =y-9.

5x-y= -9+10

5x-y= 1

EQUATION IS : 5x-y=1