find the equation of the lines passing through point (2,0) are equally inclined to the co ordinate axes .
PLEASE PUT MINUS (2,0) MY KEYS ARE NOT WORKING PROPERLY .
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If the line is equally inclined to both axes, its inclination is either 45o45o or 135o135o. So, the slope will be either tan(45o)=1tan(45o)=1 or tan(135o)=−1tan(135o)=−1.
This suggests that there will be 22 such lines in the XYXY plane, through (−2,0)(−2,0).
Line 1, slope m=1m=1. Using the slope point form, the equation will be y−0=(1)(x+2)y−0=(1)(x+2). On simplifying, y=x+2y=x+2.
Line 2, slope m=−1m=−1. Again using the slope point form, y−0=(−1)(x+2)y−0=(−1)(x+2), that is, y=−x−2y=−x−2.
Note that these lines will be perpendicular to each other.
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