find the equation of the lines which are at a distance root 3 units from the origin and pass through the point (2, 0)
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√3=√(2-x)²+(0-0)²
Squaring both sides
3=4+x²-2x
x²-2x+1=0
x²-x-x+1=0
x(x-1)-1(x-1)=0
x=1
Squaring both sides
3=4+x²-2x
x²-2x+1=0
x²-x-x+1=0
x(x-1)-1(x-1)=0
x=1
Mathemetician:
Sorry man this is not the solution.
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