Question

find the equation of the locus of a point which is equidistant from the point A(1,3) and B(-2,1).​

Answer 1

Answer:

let the point is h, k

then

√(h-1) ^2+(k-3) ^2=√(h+2) ^2+(k-1) ^2

then

expanding it

we get

h^2+1-2h +k^2+9-6k=h^2+4+4h+k^2+1-2k

the eq. is

6h +4k-5 =0

ok

follow me

gys