Math, asked by Zepy, 5 hours ago

Find the equation of the locus of point such that the sun of the squares of its distances from A(3,0) and
B(-3,0) is four times the distance from A and B.

Can i get the answers ASAP??

Answers

Answered by amitnrw
5

Given : point such that the sum of the squares of its distances from A(3,0) and B(-3,0) is four times the distance from A and B.

To Find : Locus of the point

Solution:

Let say point is P  is  ( x , y )

Square of  Distance from  A ( 3 , 0)  =  (x - 3)²  + ( y - 0)²

Square of  Distance from  B ( -3 , 0)  =  (x + 3)²  + ( y - 0)²

Distance between A and B =  √(3 + 3)² + (0 - 0)²  =  6

Sum of the squares of its distances from A(3,0) and

B(-3,0) is four times the distance from A and B.

(x - 3)²  + ( y - 0)² + (x + 3)²  + ( y - 0)²  = 4 * 6

=> x² - 6x + 9  + y² + x² + 6x + 9  + y² = 24

=> 2x²  + 2y² + 18  = 24

=> x² + y²  = 3

x² + y²  = 3 is the locus of point such that the sum of the squares of its distances from A(3,0) and

B(-3,0) is four times the distance from A and B.

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