find the equation of the median ADof a triangle whose vertices A( 0,4) , B(0,0), and C ( 8,0)
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Answer:
4√2 cm
Step-by-step explanation:
Consider triangle ABC of A(0,4) and B(0,0) and C(8,0) and D is the midpoint
By midpoint formula,
D(x,y) = (x1 + x2)/2 , (y1 + y2)/2
D(x,y) = (0+8)/2 , (0+0)/2
D(x,y) = 4 , 0
=> x = 4 , y = 0
By distance formula,
AD = √(x2-x1)^2 + (y2 - y1)^2
AD = √(4-0)^2 + (0-4)^2
AD = √4^2 + (-4)^2
AD = √16 + 16
AD = √32
AD = 4√2 cm
plz mark as brainliest...thank you
shreeji35:
nice solution
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