Find the equation of the normal to curve y 2 = 4x at the point (1, 2).
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Here, the curve is
y² = 4x ...(i)
Now, differentiating both sides with respect to x, we get
2y dy/dx = 4
⇒ dy/dx = 2/y
⇒ - dx/dy = - y/2
∴ (- dx/dy) at the point (1, 2) be
= - 2/2
= - 1
∴ the required normal be
y - 2 = - 1 (x - 1)
⇒ y - 2 = - x + 1
⇒ x + y = 3
Hope it helps! (:
Here, the curve is
y² = 4x ...(i)
Now, differentiating both sides with respect to x, we get
2y dy/dx = 4
⇒ dy/dx = 2/y
⇒ - dx/dy = - y/2
∴ (- dx/dy) at the point (1, 2) be
= - 2/2
= - 1
∴ the required normal be
y - 2 = - 1 (x - 1)
⇒ y - 2 = - x + 1
⇒ x + y = 3
Hope it helps! (:
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