Question

Find the equation of the normal to the curve 3x^2-y^2=8

Answer 1

Answer:

Answer is y-y1=-y1/3x1 (x-x1)

Step-by-step explanation:

EQ of normal is

y-y1=-dx/dy (x-x1)

and differentiating the equation of the curve

3x^2-y^2=8

=6x1-2y1dy/dx=0

=dy/dx=3x1/y1

=dx/dy=y1/3x1

now put the valies and get the answer