find the equation of the normals to the curve y=x³+2x+6 which are parallel to the line x+14y+4=0
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p(y)=x+14y+4=0
p(x^3+2x+6)=x+14y+4=0
=x+14(x^3+2x+6)+4=0
=×+14×^3+28×+84=0
=14×^3+29×+84=0
p(x^3+2x+6)=x+14y+4=0
=x+14(x^3+2x+6)+4=0
=×+14×^3+28×+84=0
=14×^3+29×+84=0
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