IN TRIANGLE ABC, 2 ANGLE A= 3 ANGLE B = 6 ANGLE C, THEN FIND ANGLE A, ANGLE B, AND ANGLE C.
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Answered by
5
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Hey friend...
2 A = 3 B = 6 C
B = 2/3 A,
C = 2/6 A = 1/3 A
We know that
Sum of interior angles of a triangle are 180°
A + B + C =180
A + 2/3 A + 1/3 A = 180°
2 A = 180
A = 90°
≡^ˇ^≡
≧∇≦
Hope helped!
❤❤❤❤❤
Hey friend...
2 A = 3 B = 6 C
B = 2/3 A,
C = 2/6 A = 1/3 A
We know that
Sum of interior angles of a triangle are 180°
A + B + C =180
A + 2/3 A + 1/3 A = 180°
2 A = 180
A = 90°
≡^ˇ^≡
≧∇≦
Hope helped!
❤❤❤❤❤
Answered by
0
Step-by-step explanation:
According to the condition in the △ABC, 2∠A=3∠B=6∠C
⇒∠A=3∠C and, ∠B=2∠C
Sum of interior angles of the triangle is 180
Hence ∠A+∠B+∠C=180
⇒3∠C+2∠C+∠C=180
⇒∠C=30
∴∠A=90 ,∠B=60 ,∠C=30
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