Find the equation of the parabola with vertex at (5,4) and focus at (-3,4)
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(y - 4)² = -32(x - 5) is the equation of the parabola with vertex at (5,4) and focus at (-3,4)
Given :
- parabola whose focus at (-3,4) and vertex at (5,4).
To Find :
- the equation of the parabola
Solution:
Vertex (5 , 4)
Focus (-3 , 4)
(y - k)² = 4p(x - h)
vertex ( h , k) and Focus ( h + p , k)
comparing with vertex and focus
=> h = 5 , k = 4
h + p = - 3
=> 5 + p = -3
=> p = - 8
Hence
(y - 4)² = 4(-8)(x - 5)
=> (y - 4)² = -32(x - 5)
(y - 4)² = -32(x - 5) is the equation of the parabola with vertex at (5,4) and focus at (-3,4)
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