Question

Find the equation of the perpendicular bisector of the line segment joining points (7, 1) and (3, 5).

Answer 1

Answer:

slope of the perpendicular bisector is 1

Equation of the perpendicular bisector is

y-y_1=m(x-x_1)y−y

1

=m(x−x

1

)

y-3=1(x-5)

x-5=y-3

x-y-2=0

Answer 2

Answer:

x-y = 2

Step-by-step explanation:

Find the equation of the perpendicular bisector of the line segments joining the points (7,1) and (3,5)

let say AB is line A(7,1) & B(3,5)

let CD is perpendicular bisector C lying at AB

C is mid point of AB

C = ((7+3)/2 , (1+5)/2) = (5 , 3)

Slope of line AB

m = (5-1)/(3-7) = 4/(-4) = -1

multiplication of slope of perpendicular lines = -1

let say slope of CD = mc

mc * m = -1

mc ( -1) = -1

mc = 1

y = mx + c

point C lies on this (5,3)

3 = 1(5) + c

c = -2

y = x -2

x - y = 2