Question

find the equation of the plane passing through the line of intersection of the planes x+2y+3z=4,2x+y-z+5=0 and making equal intercepts on the x-axis and y-axis​

Answer 1

Answer:

3x+3y+2z+1=0

Step-by-step explanation:

equation of plane passing through the lines x+2y+3z-4=0, 2x+y-z+5=0 is x+2y+3z-4+k(2x+y-z+5)=0

x(1+2k)+y(2+k)+z(3-k)+(-4+5k)=0

x-intercept =y- intercept

-(-4+5k)/1+2k=-(-4+5k)/2+k

1/1+2k=1/2+k

2+k=1+2k

1=k

require plane is,

x+2y+3z-4+1(2x+y-z+5)=0

3x+3y+2z+1=0