Question

Find the equation of the plane passing through the points (2,-1,0),(3,-4,-5) and parallel to the line 2x=3y=4z.

Answer 1

Step-by-step explanation:

general formula of equation of plane is

a(x-x1)+b(y-y1)+ c(z-z1)+d=o

here from equation

2x=4y=4z

divide this by 24

we get x/6=y/4=z/3

hence the required plane is parallel to this plane so

a=6,b=4,c=3

x1,y1,z1 are the any point given in the quotion

hence substitute the values

i.e,6(x-2)+4(y+1)+3(z)+d=0

substitude (3,-4,-5) in above equation we get d value

substitude the d value in the above equation hence we get plane equation