Question

find the equation of the radical axis of the following circles. x²+y²+4x+6y-7=0 , x²+y²-4x-6y+5=0​

Answer 1

Answer:

2x²+2y²+2

Step-by-step explanation:

(x²+y²+4x²+6x-7=0 )+(x²+y²-4x-6y+5=0)

2x²+2y²+0+0-2