Question

find the equation of the straight line having a slope 3^1/2 and passing through the point (-1,5)​

Answer 1

Step-by-step explanation:

• ..b. ..vn .......,,,.,., .,

Answer 2

Answer:

note;

the equation of the line passing through the given point (a,b) and having the slope m , is given as;

(y-b)/(x-a)=m

ie, (y-b)=m(x-a).

here, the given point is(-1,5)

and the slope,m=√3

thus , the equation of required line,

which passes through the point (-1,5)

and having the slope√3, will be given as;

=> y-5=√3{x-(-1)}

=> y-5=√3{x+1}

=> y-5=√3x+√3

=> √3x-y+(5+√3)=0

thus , the required line is;

√3x-y+(5+√3)=0