Question

Find the equation of the straight line
Parallel to the line
3x - y +7 = 0 and
Passing through the point (1, 2)​

Answer 1

Two parallel lines have the same slope, put 3x+4y=−7 in slope-intercept form: 

3x+4y=−7 

4y=−3x−7 

y=−43x−47 

 The slope is −43, so a line parallel to this has a slope of −43 also. 

Now since the equation of a line is y−y1=m(x−x1), where m is the slope of the line, therefore with point (1,2) 

We have, (y−2)=−43(x−1)⇒4(y−2)=−3(x−1)⇒4y−8=−3x+3⇒3x+4y−8−3=0⇒3x+4y−11=0

Hence, resulting linear equation is 3x+4y−11=0.