Question

Find the equation of the straight line passing through the point (5, 7) and inclined at 45° to x-axis. If it passes through the point P whose ordinate is -7 , what is the abscissa of P?

Answer 1

Answer:

Equation of line => x - y + 2 = 0

Abscissa = -9

Step-by-step explanation:

Given a line passing through (5,7)

It's inclined at 45° to x axis.

Therefore, we have,

Slope, m = tan45

=> m = 1

To find the equation of the line.

We know that,

Equation of a line passing through (x1,y1) and having slope m is given by,

• (y-y1) = m(x-x1)

Substituting the values,

Therefore, we will get,

=> y - 7 = 1(x-5)

=> y-7 = x-5

=> x-5-y+7=0

=> x-y+2 = 0

Now, it passes through the point having Ordinate equal to -7.

To find abscissa.

Substituting the value, we get,

=> x - (-7) + 2 = 0

=> x + 7 + 2 = 0

=> x + 9 = 0

=> x = -9

Hence, the equation of the line and the required value of abscissa are x-y+2 = 0 and -9 respectively.