Question

Find the equation of the straight line passing through the point (-2,5) and (3,6)​

Answer 1

Answer:

x-5y+27=0

Step-by-step explanation:

(x+2)/(3+2)=(y-5)/(6-5)

(x+2)/5=(y-5)/1

x+2=5y-25

x-5y+27=0

Answer 2

Hey mate
Refer to attachment
Hope it helps you! You can check the answer by putting x=-2 and x=3 in the equation