find the equation of the straight line passing through the point of intersection of the straight line 4x+y-4=0 and 3x+y-5=0 and parallel to the line x-2y+1=0
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slope of a line
x-2y+1 = 0 is 1/2.
line are parallel to each other so their slope will be equal.
intersection point of straight line
4x +y - 4 =0 ; 3x + y -5=0 is
on solving these equation
point iss ( -1, 8).
now equation of line having slope 1/2 passing through point (-1, 8) will be
(y-8) = 1/2 (x +1)
2y -16 =x+1
2y- x -17 =0
ans
x-2y+1 = 0 is 1/2.
line are parallel to each other so their slope will be equal.
intersection point of straight line
4x +y - 4 =0 ; 3x + y -5=0 is
on solving these equation
point iss ( -1, 8).
now equation of line having slope 1/2 passing through point (-1, 8) will be
(y-8) = 1/2 (x +1)
2y -16 =x+1
2y- x -17 =0
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hope it well help u.......
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silenteyeArun:
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