Question

Find the equation of the straight line upon which the length of the perpendicular from the origin is 2 and the slope of this perpendicular is 5/12​

Answer 1

The general equation is :    xcosα + ysinα = p

Slope = 5/12 = tanα = p/b

 So, p = 5

       b = 12

Now, cosα = b/h

         sinα = p/h

So, h² = 25 + 144

      h = 13

Thus, cosα = b/h = 12/13

          sinα = p/h = 5/13

Therefore, the equation is -

                  x×(12/13) + y×(5/13) = 2

                                   12x + 5y = 26

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