find the equation of the tangent at the end of the Latus rectum of the parabola x2=4ay
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Answer:
let tangent is drawn at (h,k) and it has a slope m
x
2
=4ay
2x=4a
dx
dy
dx
dy
=
4a
2x
=
2a
x
(
dx
dy
)
(h,k)
=
2a
h
=m
⇒h=2am
h
2
=4ak
⇒k=
4a
4a
2
m
2
=am
2
Equation of tangent is
y−k=m(x−h)
y−am
2
=m(x−2am)
y−am
2
=mx−2am
2
y=mx−am
2
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