Question

Find the equation of the tangent line to the curve
y= 4x/1+x² at the point (4,16/17). The equation of this tangent line
written in the form y = mx + b.​

Answer 1

Answer:

The slope of the tangent given is its derivative

on applying differentiation to 4x/1+x^2

u will get (4 - 4x^2)/((x^2+1)^)2

on substituting x = 4

u will get -60/289

which is the slope

therefore we can use slope point form and write

m(x-4) = (y-16/17)

-60/289(x-4) = y - 16/17

therefore y = (-60/289)x + 256/149