Question

Find the equation of the tangent line to the parabola y=x^2 at the point (1,1)

Answer 1

Step-by-step explanation:

plzzz give me brainliest ans and plzzzz follow me

Answer 2

Answer:

2x-y-1 =0

Step-by-step explanation:

Concept = Equation of tangent on Parabola

Given= Equation of parabola and  a point

To Find= Equation of Tangent on given point

Explanation= We have the curve Parabola as y=$x^{2}$ .

Thus for finding the tangent we need slope so we differentiate the curve with respect to x and get slope 'm'

=> m= dy/dx

=> m=d($x^{2}$)/dx = 2x.

so, the slope of tangent on given point(1,1)

m= 2*1 = 2.

Equation of Tangent with a point and slope is $(y-y_{1}) = m(x-x_{1} )$

applying the point (1,1) in given equation we get,

y-1 = 2(x-1)

=> y-1=2x-2

=> 2x-y=1

∴ The equation of tangent is 2x-y-1 =0.

#SPJ2