Question

find the equation of the two straight lines passing through the points -1,1 inclined at am angle of 45° to the line 2x-5y+7=0.​

Answer 1

Answer:

10xy=0

Step-by-step explanation:

10xy=0+45°

55°=10xy

Answer 2

Answer:

Correct option is

B

3x+y=5

Let y=mx+c be the equation then,

we know that when angle between two line is θ, then

tanθ=

1+m

1

m

2

m

1

−m

2

tan45°=

1+m⋅2

m−2

⇒m−2=2m+1

⇒m=−3

∴y=−3x+c passes through (1,2)

∴c=2+3=5

∴y+3x=5 is the equation.

Video Explanation