Math, asked by sudhanagendra1996, 2 days ago

Find the equation that formed increasing each root of 2x²- 3x-1=0 by 2

Answers

Answered by ashishamway152000
2

Answer:

Answer: 2x^2-5x+3=0.

Step-by-step explanation: Initial equation: 2x^2-3x-1=0. Roots by solving it: -1 & -1/2. Roots of new equation by increasing each by 2: -1+2=1 & -1/2+2=3/2. By having the roots we can put as: (x-1)(2x-3)=0. 2x^2-3x-2x+3=0. And get new equation:

2x^2-5x+3=0.

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