Question

Find the equation to the line parallel to 3x-4y+6=0 and passing through the mid point of the points (2,3) and (4,-1)​

Answer 1

Answer:

3x-4y-5=0

Step-by-step explanation:

mid point of (2,3) and (4,-1)

=( 2+4/2,3-1/2)

or(3,1)

any line parallel to 3x-4y+6=0

is of the form 3x-4y+c=0

This line passes through(3,1)

So 3*3-4*1+c=0

c=4-9=-5

Thus the equation is:

3x-4y-5=0

Answer 2

Answer:

3x - 4y - 5 = 0

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