The average molar mass of a mixture of methane and ethane present in the ratio of a:b is found to be 20 g/mol.if the ratio were reversed ,what would be the molar mass of the mixture ?
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Solution:-
Given that the methane an ethane present in the mixture in the ratio a:b.
Average molar mass of mixture =20g/mol
a+b
16a+30b
=20
⇒16a+30b=20a+20
⇒10b=4a⇒
b
a
=
2
5
If the ratio is reversed, i.e., methane an ethane present in the mixture in ratio b:a.
a+b
16b+30a
=
1+
b
a
16+30
b
a
=
1+
2
5
16+30(
2
5
)
=
2
7
16+75
=26
Hence if the ratio is reversed, the molar mass of the mixture will be 26g/mol.
Explanation:
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