"Find the equation to the straight line cutting off intercepts 3 and 2 from the axes."
All I need to know is which point is the intercept of which axes.
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hey here is your answer...
we know that equation of line having intercept A and B on X and Y axis respectively...
written as
X/A + Y/B = 1
i.e. BX +AY = AB ...
let the intercept on X axis is 3 and on Y axis is 2 then equation will be ...
X/3 + Y/2 = 1
i.e 2X + 3Y = 6
and let the intercept on X axis is 2 and on Y axis of 3 then equation will be
X/2 + Y/3 = 1
i.e 3X + 2Y = 6
we know that equation of line having intercept A and B on X and Y axis respectively...
written as
X/A + Y/B = 1
i.e. BX +AY = AB ...
let the intercept on X axis is 3 and on Y axis is 2 then equation will be ...
X/3 + Y/2 = 1
i.e 2X + 3Y = 6
and let the intercept on X axis is 2 and on Y axis of 3 then equation will be
X/2 + Y/3 = 1
i.e 3X + 2Y = 6
ishetabhatt:
Thank you! So, we'll have two cases for the equation?
yeah ...
that depends on you . which one you want to make x intercept or y intercept ...
Cool, thanks!
welcome
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