find the equation to the tangent and normal to curve y=3x-x+1 at(1,3)
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Answered by
2
y=3x-x+1
Take: 1 as x
3 as y
substituting x and y in equation we get:
3=3(1)-1+1
3=3-1+1
3=3
therefore 3-3=0
Hope it helps u
Take: 1 as x
3 as y
substituting x and y in equation we get:
3=3(1)-1+1
3=3-1+1
3=3
therefore 3-3=0
Hope it helps u
alok94:
no its helpful for me
Answered by
2
The answer is correct mark in brain list please
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