Math, asked by Regineiskyut, 6 months ago

Find the equation whose roots are

1/3 and -7/2

A. 3x2 + 8x + 7 = 0
B. x2 + 3x + 6 = 0
C. 6x2 + 19x - 7= 0 D. 7x2 - 18x + 6 = 0

Answers

Answered by reenasharmadurbhaka
10

Step-by-step explanation:

option C will be the equation which is having the roots 1/3, -7/2

Attachments:
Answered by kundumayurika10
4

Answer:

c

Step-by-step explanation:

x2-(b/a) x+(C/a) =0

where 1/3+(-7/2)=-(b/a)

19/6=b/a

and 1/3×(-7/2)=c/a

-7/6= C/a

putting the value of b/a and c/a we get from the equation x2+(19/6)x-(7/6)=0

6x2+19x-7=0

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