Question

find the equations of the tangent and the normal to the parabola y square = 16 X at the point 1,4​

Answer 1

Answer:

please mark as brainliest and follow

Step-by-step explanation:

Correct option is

C

x+2y=9

y

2

=16x

⇒2y

dx

dy

=16

⇒∴

dx

dy

=

y

8

Thus slope of tangent at (1,4) is m=2

∴Slope is normal is =−

2

1

Therefore, the equation of normal at (1,4) is given by, (y−4)=−

2

1

(x−1)

⇒x+2y=9

Answer 2

Step-by-step explanation:

x+2y=9

y

2

=16x

⇒2y

dx

dy

=16

⇒∴

dx

dy

=

y

8

Thus slope of tangent at (1,4) is m=2

∴Slope is normal is =−

2

1

Therefore, the equation of normal at (1,4) is given by, (y−4)=−

2

1

(x−1)

⇒x+2y=9

Hence, option 'C' is correct.