Question

Find the equilibrium constant Kc for the reaction: HCl (g) ⇌ 1⁄2 H2 (g) + 1⁄2 Cl2 (g), given that Kc of the equilibrium H2 (g) + Cl2 (g) ⇌ 2 HCl (g) is equal to 6

Answer 1

Answer:

H2 (g) + Cl2 (g) ⇌ 2 HCl (g) has Kc =6

==⟩

HCl (g) ⇌ 1⁄2 H2 (g) + 1⁄2 Cl2 (g) will have Kc =1/6

[{ on reversing the reaction the equilibrium constant gets reciprocal}]

since, reaction

H2 (g) + Cl2 (g) ⇌ 2 HCl (g) having Kc =6

is multiplied by half

==⟩

Knet === (1/6)^1/2

[{( if original reaction have equilibrium constant k, and reaction is multiplied with any reaction coefficient N then new equilibrium constant will be (Keq)^N. )}]

==⟩ Knet =√(1/6)