Question

find the equivalent capacitance of a cube whose each edges have capacitors C ..​

Answer 1

Applying the Kirchoff’s second law across diagonal points A and B to find the charge distribution across the branch of the circuit, and find the equivalent capacitance. Suppose the points A and B are connected to a battey. The charges appearing on some of the capacitors are shown in figure suppose the positive terminal of the battery supplies a charge +Q through the point A. This charge is divided on the three plates connected to A. Looking from A, the three sides of the cube have identical properties and hence, the charge will be equally distributed on the three plates. Each of the capacitors a, b and c will receive a charge Q/3. The negative terminal of the battey supplies a charge –Q through the point B. This is again divided equally on the three plates connected to B. Each of the capacitors d, e and f gets equal charge Q/3. Now consider the capacitors g and h. As the three plates connected to the point E form an isolated system, their total charge must be zero. The negative plate of the capacitor has a charge -Q/3. The two plates of g and h connected to E should have a total charge Q/3. By symmetry, these two plates should have equal charges and hence each of these has a charge Q/6. The capacitors a, g and d have charges Q/3, Q/6 and Q/3 respectively.

We have,VA – VB = (VA – VE) + (VE – VF) + (VF – VB)

= (Q/3)/C + (Q/6)/C + (Q/3)/C = 5Q/6C

Ceq = Q/VA – VB = (6/5)C.

mark as branliest answer