Question

Find the equivalent fraction of 3 / 5 having

(a) denominator 20

(b) numerator 9

(c) denominator 30

(d) numerator 27

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Answer 1

$\huge\underline\mathrm{SOLUTION:-}$

(a) We require denominator 20

Let M be the numerator of the fractions

∴ M / 20 = 3 / 5

5 × M = 20 × 3

M = (20 × 3) / 5

= 12

• Therefore the required fraction is 12 / 20

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(b) We require numerator 9

Let N be the denominator of the fractions

∴ 9 / N = 3 / 5

3 × N = 9 × 5

N = (9 × 5) / 3

= 15

• Therefore the required fraction is 9 / 15

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(c) We require denominator 30

Let D be the numerator of the fraction

∴ D / 30 = 3 / 5

5 × D = 3 × 30

D = (3 × 30) / 5

= 18

• Therefore the required fraction is 18 / 30

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(d) We require numerator 27

Let N be the denominator of the fraction

∴ 27 / N = 3 / 5

3 × N = 5 × 27

N = (5 × 27) / 3

= 45

• Therefore the required fraction is 27 / 45

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Answer 2

Answer:

HERE YOU GO...................................

a) 3/5 * 4/4 = 12/20

b) 3/5 * 3/3 = 9/15

c) 3/5 * 6/6 = 18/30

d) 3/5 * 9/9 = 27/45

HOPE IT HELPS YOU

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