find the equivalent resistance
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hey mate,
In parallel connection,
1/R = 1/R2 + 1/R3
1/R = 1/120 + 1/40
1/R = (1 + 3)/120
1/R = 4/120
R = 30 Ω
In another parallel connection,
1/R = 1/R4 + 1/R5 + 1/R6
1/R = 1/60 + 1/60 + 1/60
1/R = 3/60
R = 20 Ω
In series connection,
R eq = R1 + 30Ω + 20Ω + R7 + R8
R eq = (100 + 30 + 20 + 80 + 100) Ω
R eq = 330 Ω
hope it helps you
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