Physics, asked by zarahzara123, 11 months ago

find the equivalent resistance ​

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Answered by kabirsingh18
1

Answer:

hey mate,

In parallel connection,

1/R = 1/R2 + 1/R3

1/R = 1/120 + 1/40

1/R = (1 + 3)/120

1/R = 4/120

R = 30 Ω

In another parallel connection,

1/R = 1/R4 + 1/R5 + 1/R6

1/R = 1/60 + 1/60 + 1/60

1/R = 3/60

R = 20 Ω

In series connection,

R eq = R1 + 30Ω + 20Ω + R7 + R8

R eq = (100 + 30 + 20 + 80 + 100) Ω

R eq = 330 Ω

hope it helps you

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