find the equivalent resistance across the two ends A and B of the circuit shown.
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Answers
Answer:
Clearly R1 and R2 are in parallel.
The equivalent resistance R12 of R1 and R2 will be given by,
★1/ R12 = 1/R1 + 1/R2
➡1/2+1/2 ( Using Given values of resistance)
or 1/R12 = 1/1
or 1/R12 = 1 ohm
Similarly ,
equivalent resistances , R34 ( of R3 and R4) , R56( of R5 and R6) and R78( of R7 and R8) will also be 1 ohm.
Now,
R12 and R34 are in series.
Their equivalent resistance , R1234 = R12 +R34
==> 1ohm + 1ohm = 2ohm
Also,
R78 and R56 are in series.
Their equivalent resistance, R5678 = R56 +R78
==> 1ohm +1ohm = 2ohm
So , The Given circuit can now be represented as shown.
Now,
R1234 and R5678 are in parallel
Their equivalent resistance, Re will be Given by,
1/Re= 1/R1234 + 1/ R5678
➡ 1/2 + 1/2 =1/1
➡ Re = 1 ohm
Thus, the equivalent resistance between A and B is 1 ohm.
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Answer:
SOLUTION:-
Clearly R1 and R2 are in parallel.
The equivalent resistance R12 of R1 and R2 will be given by,
★1/ R12 = 1/R1 + 1/R2
➡1/2+1/2 ( Using Given values of resistance)
or 1/R12 = 1/1
or 1/R12 = 1 ohm
Similarly ,
equivalent resistances , R34 ( of R3 and R4) , R56( of R5 and R6) and R78( of R7 and R8) will also be 1 ohm.
Now,
R12 and R34 are in series.
Their equivalent resistance , R1234 = R12 +R34
==> 1ohm + 1ohm = 2ohm
Also,
R78 and R56 are in series.
Their equivalent resistance, R5678 = R56 +R78
==> 1ohm +1ohm = 2ohm
So , The Given circuit can now be represented as shown.
Now,
R1234 and R5678 are in parallel
Their equivalent resistance, Re will be Given by,
1/Re= 1/R1234 + 1/ R5678
➡ 1/2 + 1/2 =1/1
➡ Re = 1 ohm
Thus, the equivalent resistance between A and B is 1 ohm.
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