Question

Find the equivalent resistance between point A and point B

Answer 1

❏ Question:-

Find :-

• Find equivalent resistance between point A and B

❏ Answer:-

We Know,

• If Register are connected in parallel , So Total Equivalent Resistance will be 1/R = ( 1/r') + (1/r")
• Where, R= Equivalent resistance , r' = First resistance , r" = second resistance

And,

• If Resister are connected in series , so Total Equivalent Resistance will be R = (r'+r").

For First Diagram :-

• r' = 2 ohm , r" = 2 ohm , in parallel

So, Equivalent Resistance of r' and r"

• 1/R' = 1/r' + 1/r"
• 1/R' = (1/2+1/2)
• 1/R' = (2/2)
• 1/R' = 1
• R' = 1 Ohm.

Now, R' = 1 Ohm , and r'" = 2 ohm are in series ,

So, Equivalent Resistance Between AB Will be

• R = (2+1)
• R = 3 ohm. [ Ans.]

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For Second Diagram :-

• r' = 2 ohm, r" = 2ohm , r'" = 2 ohm are in parallel ,

So, Equivalent Resistance will be

• 1/R' = 1/2 + 1/2 + 1/2
• 1 /R' = (1+1+1)/2
• 1/R' = 3/2
• R' = 2/3 ohm

Now, R' = 2/3 ohm and r"" = 2 ohm in connected series ,

So, Equivalent Resistance Between AB will be

• R = R' + r""
• R = 2/3 + 2
• R = (2+6)/3
• R = 8/3
• R = 2.66 ohm [ Ans]

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For Third Diagram

• r' = 2 ohm, r" = 2 ohm are connected in parallel ,

So, Equivalent Resistance will be

• R' = 1/2 + 1/2
• R' = (1+1)/2
• R' = 2/2
• R' = 1 ohm

Now, R' = 1 ohm, r"' = 2 ohm, r"" = 2 ohm are connected in series

So, Equivalent Resistance Between AB will be

• R = (R' + r'" + r"" )
• R = (1+2+2)
• R = 5 ohm [ Ans ]

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