Question

find the equivalent resistance between points A and B as shown in the given figure.
solve it!!!!​

Answer 1

Solution :

Please refer the attachment first !!

Point C and E

Two 10 Ω resistors are connected in series with each other .

Equivalent resistances for n no of resistors is connected in series is given by ,

➜   Rs = R 1 + R 2 .... + Rn

Hence ,

➜  Rs = R + R

➜  Rs = 2R

➜  Rs = 20 Ω

20 Ω  and 10 Ω  are connected in parallel combination .

Equivalent resistances for n no of resistors is connected in parallel is given by ,

➜   1 / Rp = 1 / R 1 + 1 / R 2 .... + 1 / Rn

Hence ,

➜  1 / Rp = 1 / R  + 1 / R

➜  1 / Rp = 1 / 20  + 1 / 10

➜  1 / Rp = 1 + 2 / 20

➜  1 / Rp = 3 / 20

➜  Rp = 6.6 Ω  

Point H and G

Two 10 Ω  resistors are connected in parallel combination.

➜  1 / Rp' = 1 / R  + 1 / R

➜  1 / Rp' = 2 / R

➜  Rp' = R / 2

➜  Rp' = 10 / 2

➜  Rp' = 5 Ω  

Point A and B

Rp , R , R , Rp' are connected in series with each other .

➜ R net = Rp + 2R + Rp'

➜R net = 6.6 + 20 + 5

➜ R net = 31 . 6 Ω  

The net equivalent resistance of the circuit is 31.6 Ω   .