Question

In fig. <ABC=69°,<ACB=31°,find <BDC.​

Answer 1

Answer:

90°

Step-by-step explanation:

NOTE: The sum in the photo is wrong

BC passes through the center. So it divides the circle into half i.e. semicircle.

Angle BDC = 90°

Because the angle inscribed in a semicircle is always a right angle (90°)

Hope it helps you:)