Find the equivalent resistance between points A and B in the circuit given below.
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sorry guys it's a science question but by mistakely clicked on math
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First Resistors in series = R¹ + R²
= 3 + 3
= 6 ohm
Middle resistors in series = 3 + 3
= 6 ohm
- the equivalent resistence between A and B is 1/ req
- equivalent resistance = 1/Req
- 1/ Req = 1/6+1/6+1/6
- = 3/6
- = 2 ohm
The required equivalent resistance of the circuit is 2 Ohm.
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plz attach the sample paper of class 10 left out by cbse of all the subjects.
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