Find the equivalent resistance between points A and B of the following circuit :
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5
Equivalent resistance of the circuit:-
2 ohm,4ohm,2 ohm resistances are in series combination ,then the eqvivalent resistance for them will be :-
R'= 2+4+2= 8 ohm
8 ohm and 8 ohm resistances are in parallel combination:-
1/Req.= 1/8+1/8
1/Req.= 2/8
1/Req.= 1/4
Req.= 4 ohm
2 ohm,4ohm,2 ohm resistances are in series combination ,then the eqvivalent resistance for them will be :-
R'= 2+4+2= 8 ohm
8 ohm and 8 ohm resistances are in parallel combination:-
1/Req.= 1/8+1/8
1/Req.= 2/8
1/Req.= 1/4
Req.= 4 ohm
Answered by
3
Hii frnd...
As you can see the above 3 resistors are in series...
So, it's Req would be:
R1+R2+R3
=8 ohm.
And then the resistors are in parallel...
(Here you have to assume that you have removed all the above resistors and placed an 8 ohm resistor)
Now Req for parralel
(R1*R2)/ R1+R2 (Only applied when you have to take out Req of only 2 resistors and that too in parallel)
64/16
= 4 ohm.
Here is your answer
Hope it helped u!!!
As you can see the above 3 resistors are in series...
So, it's Req would be:
R1+R2+R3
=8 ohm.
And then the resistors are in parallel...
(Here you have to assume that you have removed all the above resistors and placed an 8 ohm resistor)
Now Req for parralel
(R1*R2)/ R1+R2 (Only applied when you have to take out Req of only 2 resistors and that too in parallel)
64/16
= 4 ohm.
Here is your answer
Hope it helped u!!!
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