Question

Find the equivalent resistance between terminals a and b

Answer 1

Answer

The equivalent resistance would be 9.6 ohms

Please find the attachment to understand the solution better.

Step-by-step explanation:

Answer 2

Answer:

The equivalent resistance between them is 9.6 ohm.

Step-by-step explanation:

To find the equivalent resistance between terminals a and b

Step 1

Equivalent resistance between two parallel combinations,

$\frac{1}{R} = \frac{1}{\frac{1}{R_{1} } +\frac{1}{R_{2} }+\frac{1}{R_{3} } }$

Here $R_{1}$ and $R_{2}$ are parallel combinations,

$R_{p1} =\frac{1}{\frac{1}{20}+\frac{1}{30} }$

$= \frac{1}{\frac{24+16}{284} }$

$= \frac{600}{50}$

= 12 ohm.

Step 2

Now, $R_{3}$ and $R_{4}$ are in parallel combination,

$R_{p2} =\frac{1}{\frac{1}{60}+\frac{1}{40} }$

$= \frac{1}{\frac{60+40}{2400} }$

$= \frac{2400}{100}$  

= 24ohm.

Step 3

Now, we get $R_{p1}$ and $R_{5}$ are in the series

$R_{s} = (12+4)$

= 16 ohm.

Now, $R_{s}$ and $R_{P2}$ are in parallel combination,

$R_{E} =\frac{1}{\frac{1}{16}+\frac{1}{24} }$

$= \frac{1}{\frac{24+16}{384} }$

$= \frac{384}{40}$

= 9.6 ohm.

Therefore, the equivalent resistance between the terminals a and b is 9.6 ohm.

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