find the equivalent resistance betweenA and B in the following circuit
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5)
Given:-
Resistors = 9 (each of 2 ohm)
We know that Resistors R1,R2 and R3 are in series
So, Req = R1+R2+R3
= 2+2+2
= 6ohm
We know that Resistors R4,R5 and R6 are in series
So, it is 6 ohm
We know that Resistors R7,R8 and R9 are in series
So, it is 6ohm
Now we know that Three resistors are in parallel
So, Req = 1/R1+1/R2+1/R3
= 1/6+1/6+1/6
= 1.99996ohm.
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