Question

Find the equivalent resistance in the following circuit
The 7 the question in the figure

Answer 1

Given:

Given circuit diagram.

To Find:

To calculate the equivalent resistance in the following circuit.

Solution:

Here resistor of 1Ω and 1Ω are connected in parallel position, so equivalent resistance $\mathbf{R_{1}}$:

$\mathbf{\dfrac{1}{R_{1}}=\dfrac{1}{1}+\dfrac{1}{1}}$

On solving:

$\mathbf{R_{1}=\dfrac{1}{2}=0.5}$

Here resistor of 2Ω and 2Ω are connected in parallel position, so equivalent resistance $\mathbf{R_{2}}$:

$\mathbf{\dfrac{1}{R_{2}}=\dfrac{1}{2}+\dfrac{1}{2}}$

On solving:

$\mathbf{R_{2}=1}$

We see that  3Ω , 3Ω, $\mathbf{R_{1}\ and \ R_{2}}$ are in series, so equivalent resistance:

$\mathbf{Equivalent\ resistance = 3+3+ R_{1} + R_{2}}$

On putting respective value in above equation:

$\mathbf{Equivalent\ resistance = 3+3+ 0.5 + 1}$

Equivalent resistance = 7.5 Ω

Means equivalent resistance in the following circuit is 7.5Ω

Answer 2

Answer:

Step-by-step explanation:

The Resistance connected in parallel

R=1/R1 +1/R2

R=1/1+1/1

R=0.5ohm

Then 2ohm and 2ohm in parallel

R=1ohm

Then ,3ohm,3 ohm, R1 ,R2 are in parallel

So,R=R1+R2+R3+R4

R=7.5ohm