Question

Find the equivalent resistance of the following figures.
Give your answer with detailed explanation. (necessary steps)​

Answer 1

Answer:

$\huge\boxed{Answer}$

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a) Figure 'a ' is type of parallel connection

Formula =

$\frac{1}{r1 } + \frac{1}{r2} \\ = \frac{1}{2} + \frac{1}{2} = \frac{2}{2} ohm = 1ohm$

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c) Figure 'c' is also parallel connection

Formula =

$\frac{1}{r1 } + \frac{1}{r2} \\ = \frac{1}{1} + \frac{1}{1} = \frac{2}{1} \\ = \frac{1}{2} ohm \\ \: \: \: \: \:$

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b) Figure 'b' is also parallel connection

Formula =

By applying parallel's formula

We'll get the answer 1/R = 5/2

==> R = 2/5 ohm

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d) Figure ' d' is both parallel & series connection

Using parallel's formula

Formula = 1/R1 +1/R2 =1/1 +1/1 = 2/1

==> R = 1/2 ****

1/R1 + 1 R2 = 1/1+ 1/1 = 2/1

==> R=1/2***

Applying series's formula

=R1+R2= 1/2+1/2 = 2/2ohm

= 1 ohm

^❤^ Hope this'll help U Loveen

Answer 2

Answer:

Explanation:

(a) is parallel.. so resistance is 1/Rn= 1/2 +1/2

Rn=1 ohm

(b)Same way as (a)

(c) Same way as (a)

(d) looks complicated but if we redraw the diagram(don't keep circuits in diamond shape),it will be easier to solve

1/Rn=1/2+1/2(as add series and then parallel)

Rn=1 ohm