Question

Find the equivalent weight of: a) CaCo3 b) K2So4* Al2(SO4)3*24H2O (Mol. mass=M)

Answer 1

we know that
equivalent weight= molecular mass/number of electron involved
i) Equivalent weight of CaCO3:
molecular mass of CaCO3=40+12+3X16
                                           =100u
molar mass=100g
no. of electrons involved is 2
equivalent weight=100/2
50g
case 2) Equivalent weight of K₂SO₄.Al₂(SO₄)₃.24H₂O
molecular mass=2x39+32+1x4+2x27+3x(16+4x16) +24 (2x1+16)
                           =900u
molar mass=900g
no. of electron involved=8
=900/8
112.5g